Question

In 10 gms of mixture of h2 and he , the partial pressure of he is 190 mm. What is the h2

Answer 1

n(no.of moles) of H2= 10/2

=5

n of He=10/4

=2.5

n(total)=7.5

P.P(H2)=X(H2){mole fraction} × P(t){total pressure} .......(1)

P.P(He)=X(He) × P(t).....(2)

Divide 1 by 2

We get.......380 mmHg....

Hope this helps...(You should calculate mole fraction yourself)