Question

In 10 s, 3 *10^20 free electrons enter one end of a
conductor and leave the other end. The current is​

Answer 1

Answer:

current will flow because that amount of current is fulfill for that

Answer 2

The current will be 4.8 A.

Step by step explanation-

Given:

No of electrons= 3×$10^{20}$

time= 10 secs

To Find: Current (I) passing through the conductor

Formula used: Q=ne

where Q= charge

           n= no of electrons

           e= charge on one electron, which is 1.6×$10^{-19}$

∴ Putting the given values in the above formula we get,

Q= 3×$10^{20}$ × 1.6×$10^{-19}$

⇒ Q= 4.8 ×10

⇒Q= 48 C

We know,

$I= \frac{Q}{t}$

where:  I= current passed, Q= charge and t= Time

∴Putting the values, we get

$I= \frac{48}{10}$

⇒$I= 4.8A$

Hence, the current passing the conductor will be 4.8 A.