Question

In 10 s, a charge of 25 C leaves a battery, and 200 J of energy..
(a) What is the p.d. across the battery ?
(b) What current flows from the battery ?​

Answer 1

Answer:

a) W=VQ

V=W/Q

=200/25

=8V

b) I=Q/T

=25/10

2.5A

Explanation:

Answer 2

Explanation:

potential difference is 1 v across two points is equal to workdone of 1 j performed on 1 c

hence to transfer 25C workdone is 200 j means the potential difference = 200×25 =5000v

charge = current×time hence the current is 25 c / 10s =2.5 A