Question

In 10 seconds a charge of 25 C leaves a battery and 200 joule of energy is delivered to an outside current.
A. find the potential difference across the battery.
B. find the current flowing through the circuit.

Answer 1

given
electric charge=25 C
work done = 200 joule
time=20 sec

A. P.D = W/Q
P.D = 200/25
P.D = 8 Volt

then,
B. I = Q/T
I= 25/10
I = 2.5 Ampere


i hope it is helpful for you

Answer 2

Answer:

Explanation:

Here time 10 second

Charge =25coulomb

Work done =200joules

V=W/Q

V=200joule/25C

V=8volt

Now

I = Q/T

I = 25/10 sec

I= 2.5ampere