in 10 years A will be twice as old as B was 10 years ago if A is now 9 years older than B the present age of B is......
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Answered by
5
Let B's age = x years.
Then, As age = (x+ 9) years.
(x+9+10)=2(x—10)
hence x=39.
Present age of B = 39 years
Then, As age = (x+ 9) years.
(x+9+10)=2(x—10)
hence x=39.
Present age of B = 39 years
Answered by
2
let age of a be x+9 yrs
let age of b be x yrs
10 years later
age of a=x+9+10
= x+19
10 years ago
age of b=x-10
ATQ
x+19 = 2(x-10)
x+19= 2x-20
2x-x = 19+20
x= 39
hence b is 39 years old
let age of b be x yrs
10 years later
age of a=x+9+10
= x+19
10 years ago
age of b=x-10
ATQ
x+19 = 2(x-10)
x+19= 2x-20
2x-x = 19+20
x= 39
hence b is 39 years old
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