Question

In 10 years the sum of the ages of two brothers will be two times the sum of their present ages. If one of them is 2 Years older than the other find the present ages

Answer 1

Heya!Here is your answer friend ⏬
--------------------------------------------

Let age of one brother be X years

The age of second brother = X+2 years .

After 10 years ,

( X+10). + (X+12) = 2 (X + X +2)

2X + 22 = 4 X + 4

22-4 = 4X -2X

2X = 18

X= 9 years .

Age of brothers are 9 and 11 years .

-----------------------------------------------------☺☺--------------------------------

Answer 2

let present age of younger brother=x yrs
elder brother's age=x+2 yrs
x+10+x+2+10=2(x+x+2)
2x+22=4x+4
2x=18
x=9
the ages of brothers are 9 & 11 yrs