Question

In 100 m race, A covers the distance in 36 seconds and B in 45 seconds. In this race A beats B by:

Answer 1

forA s=d/t=100/36×18/5=10km/hr; forB s=d/t=100/45×18/5=8 km/hr ::different between speed=10-8=2km/hrs ::

Answer 2

$\Large{\fcolorbox{grey}{yellow}{ \red{Correct} \pink{Answer} is :}}$

20 m ✔

$\Large\tt\pink{\underline{Explanation :}}$

☞Distance covered by B in 45 seconds = 100 meters

☞Distance covered by B in 9 seconds = (100/45) * 9 = 20 meters

☞So, when A covers 100 meters in 36 seconds, B was 20 meters away from the winning post. Thus, A beats B by 20 meters.