Question

in 100 set of 10 tosses of a coin ,the no. of cases you expect 7 head and 3 tail is​

Answer 1

Answer:

Step-by-step explanation:

Based on the description, I understand that you toss a coin ten times to see if you get 77 heads and 33 tails. Repeat this experiment 9999 more times.

The probability of getting 77 heads and 33 tails is (12)10×(107)(12)10×(107) if you flip a coin 1010 times. Your expected number after 100

100 sets is just the previous number times 100

100.

Answer 2

12 Cases expected 7 head and 3 tail in 10 tosses of coin in 100 sets.

Given:

100 set of 10 tosses of a coin

To Find:

The no. of cases expected 7 head and 3 tail

Solution:

Probability of head p = 1/2

probability of not head ( tail) q = 1/2

n = 10

P(x) = ⁿCₓpˣqⁿ⁻ˣ

head = 7 , x = 7

P(7) = ¹⁰C₇(1/2)⁷q¹⁰⁻⁷

= 120 /1024

Expected in 100 Cases = 100 x 120/1024 ≈ 11.72 ≈ 12

Hence, 12 Cases expected with  7 head and 3 tail in 10 tosses of coin in 100 sets.