Question

In 10seconds, a body of mass 6kg is dragged 8m with uniform velocity across a floor by a steady force of 20N. Then the KE of the body is

Answer 1

1/2mv^2 = KE
(1/2)(6)(0.8)^2=1.92J


                                                            v=distance/time
                                                             v = 8/10
                                                              v=0.8

Answer 2

Given :

Time (t) = 10 s

Mass (m) = 6 kg

Distance (s) = 8 m

Force (F) = 20 N

To find :

Kinetic Energy (KE) of the body.

Solution :

Kinetic Energy = 1 / 2 mv²

v is not given.

So, find v by using formula :

Velocity = Distance / Time

v = s / t

v = 8 / 10

v = 0.8 m/s

Now, put the value of v in the formula of kinetic energy.

KE = 1 / 2 mv²

KE = 1 / 2 × 6 × 0.8²

KE = 1.92 J

Therefore, Kinetic Energy of the body is 1.92 J.