Question

In 12 years a man will be three times as old as his son;the difference of their present ages is 30 years.Find their present ages

Answer 1

at present:
let x=son's age
30+x=father's age
...
12 years hence:
x+12=son's age

30+x+12=42+x=father's age
...
42+x=3(x+12)
42+x=3x+36
2x=6
x=3
30+x=33
...
son's present age=3
father's present age=33

Answer 2

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