In 12th orbit of H-atom, mv12r12 = ?
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Explanation:
According to Bohr's second postulate, mvr=
2π
nh
where m be the mass of an electron, v be the velocity and r be the radius of orbit in which the electron revolves around the nucleus.
So, v=
2πmr
nh
Here, the centripetal force is provided by the electrostatic force of attraction between electron and nucleus.
Thus,
r
mv
2
=
r
2
k(Ze)(e)
⇒r=
mv
2
kZe
2
Substituting the value of v:
r=
4π
2
mkZe
2
n
2
h
2
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