In 1453, during the siege of Constantinople, the Turks used a cannon capable of
launching a stone cannonball with a mass of 5.40 × 102 kg. Suppose a soldier
dropped a cannonball with this mass while trying to load it into the cannon. The
cannonball rolled down a hill that made an angle of 30.0° with the horizontal. If
5.30 × 104 J of work was done by gravity on the cannonball as it rolled down a hill,
how far did it roll?
Answers
The distance through which it is rolled down the hill is 20m.
Given,
Mass of cannonball =5.40 * 10² Kg
Angle of inclination of hill= 30°
Work done= 5.30 *10⁴ J
To find,
Distance travelled by the cannonball (s)=?
Solution,
During motion on an inclined plane:
a=gsinθ =constant
∴ Force(F) =ma =mgsinθ
Now,
Work done (W) = ∫F.ds =mgsinθ.s
5.30 *10⁴ =5.40 × 10² *9.8*sin30° .s
s= 20 m
Hence, the distance through which it rolled down the hill is 20m.
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Answer:
The distance through which it rolled down the hill is 20m.
Explanation:
From the above question,
Total mass = 5.40 × 102 kg.
Suppose a soldier dropped a cannon-ball with this mass while trying to load it into the cannon.
The cannon- ball rolled down a hill that made an angle of 30.0° with the horizontal.
The work was done by gravity on the cannonball as it rolled down a hill of 5.30 × 104 J.
The distance through which it is rolled down the hill is 20m.
Given,
Mass of cannonball = 5.40 * 10² Kg
Angle of inclination of hill = 30°
Work done = 5.30 *10⁴ J
We have to find the distance travelled by the cannonball (s)
Hence,
During motion on an inclined plane:
a = gsinθ = constant
Force(F) = ma = mgsinθ
Now,
Work done (W) = ∫F.ds =mgsinθ.s
5.30 *10⁴ = 5.40 × 10² *9.8*sin30° .s
s = 20 m
Hence, the distance through which it rolled down the hill is 20m.
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