Question

In 15 years, Maya will be twice as old as David is now. In 15 years, David will be as old as Maya will be 10 years from now. How old are they now?

Answer 1

Let present ages of Maya be x and of David be y.

Then 15 years later,

Maya's age will be twice than the present age of David.

⇒ x + 15 = 2y

⇒ x - 2y = -15 ___(1)

David age will be equal to age of Maya after 10 yrs.

⇒ y + 15 = x + 10

⇒ y - x = - 5 ___(2)

On adding 2 equations we get,

→ - y = - 20 or y = 20

By susbtituting value we get,

⇒ 20 - x = - 5

→ x = 25

Hence age of Maya is 25 years and of David is 20 years.