In 18 gm of C6H12O6, find
(i) No. of molecules -
(ii) No. of C atoms
(iv) No. of H atoms
(v)No. of O atoms
(vi) No. of atoms
(vii) Atomicity of glucose
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Answered by
1
Simple formula
Mole × avagaderoseno.× atomicity.
Atomicity means = jiske no. Of atoms nikalne hain wo kitne hain like carbon =6
Then we put 6 in place of atomicity when we will find no of C atoms
Answered by
2
1) 180GM OF C6H12O6 = 6.022*10^23 MOLECULES
18 GM OF C6H12O6 = 6.022* 10^22 MOLECULES
2) 6
3) 12
4) 6
5) 6.022 * 10^22 *24
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