Math, asked by superstars205, 1 year ago

In 1930, a person’s age was 8 times that of his shown. In 1938, the father's age became ten times that of his son’s age in 1930.

Answers

Answered by swagatikameher98
0

let son's age in 1930 be x

person's age= 8x

after 8 years son= x+8 and father = 8x+8

acc. to ques. 8x+8=10x

2x=8

x=4

so. the person's age was 32 years in 1930 and hin son was 4 years

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