Math, asked by krishna5677, 1 year ago

in 1980, the age of the father was four times that of the age of his son. in 2000, the age of the father was twice that of the son. find the year of birth of the son

Answers

Answered by praneethks
5
lets us take the age of the son be x. so age of the father is 4x. after twenty years age of son is x+20 and age of father is 4x+20.according to question 4x+20= 2x+40. 2x= 20 . x=10. hence in 1980, the son is 10years old and the year of birth of son is 1970.
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