In ∆, ∠: ∠: ∠ = 2 ∶ 3 ∶ 5, then angle at B is (a) 54° (b) 126° (c) 136° (d) 64°
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∠A:∠B:∠C:∠D=1:2:3:4
So, let ∠A=x,∠B=2x,∠C=3x,∠D=4x
Therefore, by angle sum property of quadrilateral,
x+2x+3x+4x=360
10x=360
x=36o
Hence,
∠A=36o,∠B=72o,∠C=108o,∠D=144o.
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