Question

in 2000kg of water,1.5kg nacl is dissolved.calculate the molality of solution​

Answer 1

Answer:

0.048

Explanation:

1500/58.44=97.15

therefore Molality =no.of moles of solute/mass of solvent(kg)

=97.15/2000

=0.048

Answer 2

The molality of a solution essentially relates the number of moles of solute and the mass of the solvent.

More specifically, molality is defined as the number of moles of solute, which in your case is sodium chloride,

NaCl

, present in one kilogram of solvent, which is water.

To find the number of moles of sodium chloride present in your sample, sue the compound's molar mass

25g⋅1 mole NaCl58.44g=0.428 moles NaCl

Now, you know that you're dissolving this many moles of sodium chloride in

20 kg

of water. You can thus use the composition of this solution to find the number of moles of solute present in

1 kg of water 1 kg water⋅0.428 moles NaCl20kg water=0.0214 moles NaCl

Rounded to one significant figure, the number of sig figs you have for the mass of water, the molality of the solution will be

molality = 0.02 mol kg ^ -1