Question

In 2004 Colin had a salary of $7200.
(a) This was an increase of 20% on his salary in 2002.
Calculate his salary in 2002.

[2]

(b) In 2006 his salary increased to$8100.
Calculate the percentage increase from 2004 to 2006.
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Answer 1

Answer:

Let the salary of Colin be x

Step-by-step explanation:

Then,

Percentage increase in the salary = 1.20x

Actual salary in 2002 = 1.20x = $7200

x = 7200/1.2

x = 72000/12

x = $6000

Therefore his actual salary was $6000.

Hope that it helps....

If anything is wrong in the answer, then I'm really sorry.....

Answer 2

Answer:

(a) $6000

(b) 12.5%

Step-by-step explanation:

(a): Let his old salary be X

• 7200 = 120% (bc it has an increase of 20%)
•    x    = 100% (bc it was the original salary without an increase or decrease)
• Cross multiply: X= 720000/120
• X=6000

• The answer is $6000

(b): Percentage change= {(new value-old value) / old value} * 100

• His new salary is 8100, and his old salary is 7200
• So: (8100/7200) / 7200 = 0.125 * 100 = 12.5
• The answer is 12.5%

Hope this helps!!