Question

In 2016, the members of the club paid a total
Of $42 in subscription fees, In 2017, the newmber
of members increased by 20 and the subscription
fees were subsequently reduced by 10 cents per
member. The total of the subscription fees for 2017 =
was $45. How
many
members were there in
2016,​

Answer 1

Answer:

Let n = original no. of members in 2005

then

(n+20) = no. of members in 2006

:

2005 cost/member - 2006 cost/member = $.10

42%2Fn - 45%2F%28%28n%2B20%29%29 = .10

:

multiply eq by n(n+2), results:

42(n+20) - 45n = .10n(n+20)

:

42n + 840 - 45n = .1n^2 + 2n

:

-3n + 840 = .1n^2 + 2n

;

Arrange as a quadratic equation

.1n^2 + 2n +3n - 840 = 0

:

.1n^2 + 5n - 840 = 0

:

Multiply by 10 to get rid of the decimal, results:

n^2 + 50n - 8400 = 0

:

you can use the quadratic formula, but this will factor to:

(n-70) (n+120) = 0

the positive solution

n = 70 members in 2005

:

:

Check this (90 members in 2006), find the cost per member in each year.

42/70 - 45/90 =

.60 - .50 = .10 reduction