In 20sec A motor changes it's velocity from 1200 rpm to 1800rpm. In this period, the no. of rotations made by it
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Answer:
500
Explanation:
Given,
ω0=1200rpm=20rps
ω=1800rpm=30rps
t=20sec
From the rotational mechanics
ω=ω0+αt
α=tω−ω0
α=2030−20=0.5rps2
The number of rotation,
θ=ω0t+21αt2
θ=20×20+21×0.5×20×20
θ=400+100=500rotation
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