In 240 years ,a radioactive material remain 1/16th of its initial value find half life and decay constant of radioactive material
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activity of radioactive substance at any time t is given by
⇒N=N
0
e
−λt
given that
N
0
N
=
16
1
at time t=40days
⇒
16
1
=e
−40λ
⇒e
40λ
=16
⇒λ=
40
ln16
we know that
t
2
1
=
λ
ln2
after putting the value of λ in above equation
⇒t
2
1
=
ln16
ln2
×40=10
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