Question

In -2a³bc⁴÷5,write the coefficient of a³,a÷5,abc,-2ac³,-2c÷5

Answer 1

Step-by-step explanation:

triangle OEB,

OB2 = OE2 + EB2

OB2 = x2 + 52 ---(1)

In triangle OFD,

OD2 = OF2 + FD2

OD2 = (17-x)2 + 122 ---(2)

OB = OD (radius of the given circle)

(1) = (2)

x2 + 52 = (17-x)2 + 122

x2 + 52 = 172 + x2 - 2(17) x + 122

x2 + 25 = 289 + x2 - 34x + 144

x2 - x2 + 34x + 25 - 144 - 289 = 0

34x - 408 = 0

34(x - 12) = 0

x = 12 cm

By applying the value of x in the 1st equation, we get

OB2 = 122 + 52

OB2 = 144 + 25 = 169

OB = √169 = 13 cm

hope it will help you

mark.me as BRAINLIEST

waiting for notifications

thanks my answer

follow me