Question

In 2digit number the sum of its digit is 13 if the number is subtracted from the number obtained by interchaining the digit the result is 45 . Find the number

Answer 1

let the ones place =x
so tens place = 13-x
original no.= 10(13-x)+x
=130-10x+x
=130-9x
no. obtained by interchanging
new no.=10(x)+13-x
=10x+13-x
=9x+13
given
new no. - original no. = 45
(130-9x)-(9x+13)=45
130-9x-9x-13=13
130-13-9x-9x=45
117-18x=45
-18x=45-117
-18x=-72
18x=72
x=72/18
x=4
no.= 130-9x
=130-9×4
=130-36
=94
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