Math, asked by avanishchowdhury, 23 days ago

In 3+√8, find the
1/x+x​

Answers

Answered by vatsalpal13jun2009
0

Answer:

34

Step-by-step explanation:

x = 3+ √8  

x = (3+√8)(3-√8) / (3-√8)  

x = (9 -8) / (3-√8)  

x = 1/ (3 -√8)  

Or we can write 1/x = (3-√8)  

Put the value and find out  

x² +(1/x²) = x² + (1/x)²  

So x² + 1/ x² = (3 +√8)² + (3 -√8)²  

= 9+6√8+8 + 9–6√8+8

= 34. Ans.

Answered by shoaib050670
0

Step-by-step explanation:

Here

x = 3+ √8

x = (3+√8)(3-√8) / (3-√8)

x = (9 -8) / (3-√8)

x = 1/ (3 -√8)

Or we can write 1/x = (3-√8)

Put the value and find out

x² +(1/x²) = x² + (1/x)²

So x² + 1/ x² = (3 +√8)² + (3 -√8)²

= 9+6√8+8 + 9–6√8+8

= 34. Ans…………...

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