Question

In 3 coin tosses probability of obtaining exactly two tails

Answer 1

when three coins are tossed then the the number of possible out comes n=8.

E be the event of getting exactly two tails.

E={TTH,THT,HTT}

n(E)=3.therefore m=3

P(E)=m/n=3/8.

Answer 2

Answer: 0.5

:D

Step-by-step explanation:

Step 1

Find the total possible events of sample space S

S = {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}

S = 8

Step 2

Find the expected or successful events A

A = {HTT, THT, TTH, TTT}

A = 4

Step 3

Find the probability

P(A) = Successful Events

= 4/8

= 0.5

P(A) = 0.5

0.5 is the probability of getting 2 Tails in 3 tosses.