in
3. Find the percentage decrease
the weight
weight of a body when taken a = 20km below
the surface of the earth & Re= 6400
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Answer:
Here d= 32 km R= 6400 km
weight of body at depth d is mg`
=mg(1-d/R)%
decrease in weight =( mg- mg`)/mg × 100= 32 / 6400×100 = 0.5%.
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