Question

In 3 termed Arithmetic Progression, the middle term is 30. Then sum of end terms A ) 50 B) 60 C) 70 D) 30​

Answer 1

Answer:

Let the 3 terms be a−d,a,a+d

Their sum is 30

⟹a−d+a+a+d=30

3a=30

a=10

Hence the middle term is 10