In 32.2 g
Na SO .10H O 2 4 2
the number of
Na+
ions is _________
10^
(Molecular mass: 322g/mole)
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Answer:
Number of gm of oxygen in 32.2 g Na
2
SO
4
.10H
2
O is No. of oxygen atoms in one molecule =4+10=14
Thus moles of oxygen in n moles of compound=14n
Molar mass of Na
2
SO
4
.10H
2
O=46+32+64+180=322g/mol
Thus
32.2g=
322
32.2
=0.1 mols
Thus moles of O=0.1×14=1.4
So weight is
16×1.4=22.4g
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