Question

In 32.2 g
Na SO .10H O 2 4 2
the number of
Na+
ions is _________
10^
(Molecular mass: 322g/mole)

Answer 1

Answer:

Number of gm of oxygen in 32.2 g Na

2

SO

4

.10H

2

O is No. of oxygen atoms in one molecule =4+10=14

Thus moles of oxygen in n moles of compound=14n

Molar mass of Na

2

SO

4

.10H

2

O=46+32+64+180=322g/mol

Thus

32.2g=

322

32.2

=0.1 mols

Thus moles of O=0.1×14=1.4

So weight is

16×1.4=22.4g