Question

In 4.2 mg of N³-ions calculate the number of ions nad aum of protons and neutrons
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Answer 1

Answer:

1.No .of ions in nitride ion N^3- is 10(neutral nitrogen has 5 e and three electrons are added)

2. No .of moles of N^3– is

4.2/14=0.3 moles( given mass/mass of nitrogen)

3.one mole of nitride has avagadro no of nitride ions (6.022*10^23 let it be ‘N')

No.of ions in 0.3 moles is 0.3*N no of nitride ions.

4. Each ion has 8 valence electrons.

Therefore 0.3*N nitride ions have

0.3*N*8 e =14.4528*10^23 valence electrons

Answer 2

Explanation:

N

3−

= 4.2g =

14

4.2

moles =0.3 moles

1 mole of N

3−

contains 10N

A

electrons.

∴ 0.3 moles of N

3−

contains 0.3×10N

A

electrons.

=3N

A

electrons