Math, asked by hirthik9650, 1 year ago

In 4 years time a baby's age is 5 times as high as it is now,find the age of the baby.

Answers

Answered by Panzer786
6
Hey !!



Let present age of baby be X.


After 4 years age of baby = ( X + 4 ) years.





A/C,



X + 4 = 5 X




5X - X = 4


4X =4


X = 1

Present age of baby = X = 1 years.

jaisingh93: he
Answered by limelight1726
14
Heya mate

The answer of ur question is ÷

Let age of baby be 'a '

After 4 yrs age of baby will be = ( a +4 ) years

According to the condition

a +4 = 5a
5a - a = 4
4a = 4
a = 4/4
a = 1


hence, the present age of baby is 1 year










hope it helps

jaisingh93: he
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