In 4 years time a baby's age is 5 times as high as it is now,find the age of the baby.
Answers
Answered by
6
Hey !!
Let present age of baby be X.
After 4 years age of baby = ( X + 4 ) years.
A/C,
X + 4 = 5 X
5X - X = 4
4X =4
X = 1
Present age of baby = X = 1 years.
Let present age of baby be X.
After 4 years age of baby = ( X + 4 ) years.
A/C,
X + 4 = 5 X
5X - X = 4
4X =4
X = 1
Present age of baby = X = 1 years.
jaisingh93:
he
Answered by
14
Heya mate
The answer of ur question is ÷
Let age of baby be 'a '
After 4 yrs age of baby will be = ( a +4 ) years
According to the condition
a +4 = 5a
5a - a = 4
4a = 4
a = 4/4
a = 1
hence, the present age of baby is 1 year
hope it helps
The answer of ur question is ÷
Let age of baby be 'a '
After 4 yrs age of baby will be = ( a +4 ) years
According to the condition
a +4 = 5a
5a - a = 4
4a = 4
a = 4/4
a = 1
hence, the present age of baby is 1 year
hope it helps
Similar questions