in 4 years' time a baby will be 5 times as old as she is now. find her age
Answers
Answered by
163
Let the age of the baby be x years at present.
Age of baby after 4 years = (x+4) years
According to question,
Age of baby after 4 years will be five times of her present age.
Therefore,
⇒x+4=5x
⇒4=5x-x
⇒4=4x
⇒x=1
Therefore,
Present age of baby is 1 years.
HOPING THAT IT WILL HELP YOU!!!
Age of baby after 4 years = (x+4) years
According to question,
Age of baby after 4 years will be five times of her present age.
Therefore,
⇒x+4=5x
⇒4=5x-x
⇒4=4x
⇒x=1
Therefore,
Present age of baby is 1 years.
HOPING THAT IT WILL HELP YOU!!!
Answered by
54
let the present age of the baby be x.
age of the baby after 4 years = 4+x
according to the problem ,
5x = 4+x
=> 5x - x = 4
=> 4x = 4
therefore , x = 1
so the present age of the baby is 1 years.
age of the baby after 4 years = 4+x
according to the problem ,
5x = 4+x
=> 5x - x = 4
=> 4x = 4
therefore , x = 1
so the present age of the baby is 1 years.
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