Question

In 4 years time how much will rs.3650 amount to at 6% p a rate of interest

Answer 1

Answer:

to find amount firstly we will find Simple interest.

SI = P × R × T / 100

= 3650×4×6/100

=3650×24/100

=365×24/10

=8760/10

=876

amount= SI+PRINCIPAL

=876+3650

=4526

Answer 2

Answer:

Required amount money is 4526 rupees.

Step-by-step explanation:

Given,In 4 years time a certain amount of money will rs.3650 amount to at 6% p a rate of interest.

So,rate of interest = 6%

time = 4 years

principal = 3650 rupees

It is clear that it is a problem of simple interest.

We know by simple interest rule,

Amount $= p + \frac{prt}{100}$

Where p is principal,r is rate of interest,t is time.

Here amount = 3650 rupees,r = 6% and t = 4 years

So according to question,

$amount = 3650 + \frac{3650 \times 6 \times 4}{100} \\ =3650+876\\=4526$

Required amount money is 4526 rupees.

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