Question

In 40g water of 100°c, 150 g of cold water is mixed. If the temperature becomes 50°c then what is the temperature of the cold water

Answer 1

Answer:

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Answer 2

Answer:

For Hot water:

Mass=40g

S.H.C=4.2Jg−1oC−1

InitialTemp.=60oC

FinalTemp.=x

△TH=(60−x)

for Cold water:

Mass=100g

S.H.C=4.2Jg−1oC−1

InitialTemp.=?

FinalTemp.=x

△TC=10oC

Heatgivenoutbyhotwater=mc△TH

                                                         =40×4.2×(60−x)

Heatabsorbedbycoldwater=mc△TC=100×4.2×10

∴Heatgivenoutbyhotwater=Heatabsorbedbycoldwater

∴40×4.2×(60−x)=100×4.2×10

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