in 5 gram atom of silver(at.weight 108) calculate the weight of one atom of silver
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Ag has atomic mass of 108 which is equal to its 1 mole.
Acc to avagadro number 1 mole has 6.O23×10^23 atoms . Which means 108 g of Ag contains 6.023×10^23 atoms.
Therefore 5 g of silver will have : O.28 × 10^23 atoms.
Cheers!
Acc to avagadro number 1 mole has 6.O23×10^23 atoms . Which means 108 g of Ag contains 6.023×10^23 atoms.
Therefore 5 g of silver will have : O.28 × 10^23 atoms.
Cheers!
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