Question

In 5 hours A walks 2 km less than the distance Bwalks in 9 hours. In four hours A walks 11 km morethan that covered by B in three hours. The distancethat A can walk in 2 hours is​

Answer 1

Answer:

A.T.P

5A+2=9B ....(i)

4A-11=3B......(ii)

By subtracting eqn ii from i, we get

A+13=6B

=> A=6B-13

now putting this value in eqn i, we get

30B-65+2=9B

=>21B=63

=>B=3

Now A=18-13=5

Now 2A=10

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