In 5 throws with a pair of dice, what is the chance of throwing a double thrice?
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Answer:
0.03
Step-by-step explanation:
when a dice is thrown the total possibility=6
when a pair of dice is thrown total possibility = 6*6=36
so p(getting a doublet)= 6/36=1/6
P(not getting a doublet)=1-1/6=5/6
This is for 1 trial.
as we have performed 5 trials, and getting 3 doublet= ⁵C₃×(1/6)³×(5/6)⁵⁻³
as we have taken 1/6 for getting a doublet so 3times doublet and 5-3=2 times non doublet.
So probability= 5!/(2!*3!) ×1/216×25/36
= 0.03 or 3/100
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