Math, asked by kaurranjeet57424, 5 months ago

(in) 50 cm, 80 cm, 100 cm
(iv) 13 cm, 12 cm, 5 cm
D
2. PQR is a triangle right angled at P and M is a
point on QR such that PM IQR. Show that
PM=QM.MR.
3. In Fig. 6.53, ABD is a triangle right angled at A
and ACIBD. Show that
(1) AB2=BC.BD
(ii) AC=BC.DC
(i) ADP = BD.CD
B
Fig. 6.53​

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Answered by aaryan03123
0

Answer:

sorry for the not replying answer

Answered by halimashaikh978
0

Answer:

answer is 1 is your answer

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