In 50 gram of calcium carbonate find the number of carbon , oxygen, and calcium atom
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Given mass = 50 g
Molecular weight of CaCO3 = 100 g / mol
No. of moles (n) = Given mass (m) / Molecular weight (M)
n = 50 / 100
n = 1 / 2
n = 0.5
No. of molecules = n * 6.022 * 10²³
= 0.5 * 6.022 * 10²³
= 3.011 * 10²³
No. of atoms = 5 * 3.011 * 10²³
= 15.055 * 10²³
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Molecular weight of CaCO3 = 100 g / mol
No. of moles (n) = Given mass (m) / Molecular weight (M)
n = 50 / 100
n = 1 / 2
n = 0.5
No. of molecules = n * 6.022 * 10²³
= 0.5 * 6.022 * 10²³
= 3.011 * 10²³
No. of atoms = 5 * 3.011 * 10²³
= 15.055 * 10²³
Read more on Brainly.in - https://brainly.in/question/1120056#readmore
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