Question

In 500 ml water which gm H3PO3 if added then normality will be 0.5(N)​

Answer 1

Answer:

normality=weight of H3PO3×1000/eq weight of the H3PO3×volume here normality is 0.5N, eq weight of H3PO3 is 41 , volume is 500 ml putting the value in equation .. 0.5=w×1000/41×500 ,, 0.5=w×2/41 ,, w=0.5×41/2

w=10.5gm ans