Question

In 50g of Sodium Chloride (NaCl), what will be the number of atoms of Chlorine in terms of Avagadro number (6.022 × 10^23)?​

Answer 1

Answer:

5.15x10^23

Explanation:

n=m/M

n= 50/58.44

n= 0.855 therefore

N=nxNa

=0.855 x 6.022x 10^23

=5.14881x10^23 approximately 5.155x 10^23