Question

In 5gm of Ag (atm wgt of Ag =108) calculate the wgt of 1 atom of Ag​

Answer 1

Answer:

It's answer is 17.93×10^-23gm

Explanation:

N atoms of Ag weigh 108gm

therefore 1atom of Ag weighs 108/N ( Avogadro's no)

108/6.023×10^-23 = 17.93× 10^-23

Answer 2

Answer:

Atomic weight of Ag = 108

1 mole= 6.022×10^23 atom

6.022×10^23 atom= 108 gm of Ag

1 atom= 108/6.022×10^23

=17.93× 10^-23 gm