Question

In (6^41 * 3^56 * 11^7 * 65^9), find the total number of prime factors

Answer 1

$6^{41} \times 3^{56} \times 11^7 \times 65^9 \\ \\ (2\times3)^{41}\times3^{56}\times11^7\times(5\times13)^9 \\ \\ 2^{41}\times3^{41}\times3^{56}\times11^7\times5^9\times13^9 \\ \\ 2^{41}\times3^{97}\times5^9\times11^7\times13^9$

Okay, now the number is prime factorized.

See, there are 5 prime numbers: 2, 3, 5, 11 and 13.

So the answer is 5.

Thank you. Have a nice day. :-))

       

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