Chemistry, asked by sundarbaba6708, 1 year ago

In 600 gram of mixture of salt and water, there is 40 % water. How much water should be converted to steam so that water in the mixture remains 25 %.

Answers

Answered by reshmachandrika64
3

Answer:

50 grams

Explanation:

Given that 750 gms of water contains 30% water or 30/100×750=225 gms of water

Let x grams of water be evaporated such that the solution now contains 25% water

(225-x)/(750-x)=25% or 25/100

(225-x)/(750-x)= 1/4

4(225-x)=750-x

900-4x = 750-x

900-750 = 4x-x

150 = 3x

x= 50 gms

Similar questions