Question

In 63.0 mole of phosphorus calculate:

(a) No. of atoms of phosphorus

(b) No. of molecules of phosphorus
(Atomic mass of P = 31u)​

Answer 1

Answer:

(b) 1mole of P4 molecule = 6.022×10^23 molecules

63 mol of P4 molecule = 63×6.022×10^23

molecules

(a) No.of atoms = 63×6.022 × 4

= 252×6.022