Question

In 7 days a machine cleans 5.6*10000000 kg weight of iron ore. How much iron ore will it clean for 45 days ?

Answer 1

Answer:

Iron ores occur in igneous, metamorphic (transformed), or sedimentary rocks in a variety of geologic environments. ... The most widely distributed iron-bearing minerals are oxides, and iron ores consist mainly of hematite (Fe2O3), which is red; magnetite (Fe3O4),

Answer 2

In 45 days the machine will clear 36×10^7 kilograms.

• Given data :

In 7 days the machine clears 5.6 × 10000000 kilograms of iron ore.

• At first we have to calculate the amount of iron ore that the machine can clear in one day.

So,

The machine clears in 7 days = 5.6 × 10000000 kilograms

The machine will clear in 1 day = 56000000/7 = 8000000 kilograms.

• At last we have to calculate the amount of iron that the machine will clear in 45 days.

So,

In 1 day machine clears = 8000000 kilograms

In 45 days the machine will clear = 8000000×45 = 8 × 1000000 × 45 = 1000000 × 360 = 1000000×10×36 = 36×10000000 = 36 × 10^7 kilograms.

So,in 45 days the machine will clear 36×10^7 kilograms of iron ore. (Answer)