Question

In ∆, ∠=70°,∠=50° ∠ . ℎ ∠.

Answer 1

Answer:

Angle D = 100°

Step-by-step explanation:

In ∆ ABC

ANGLE A+ ANGLE B+ ANGLE C = 180°

50°+70°+ANGLE C = 180°

ANGLE C=180-120

ANGLE C =60°

NOW,

LINE CD IS PERPENDICULAR TO AB AND A PERPENDICULAR DIVIDES A LINE INTO TWO EQUAL PARTS.

SO, ANGLE C = 60×1/2=30

NOW,

IN ∆ ADC;

ANGLE A+ANGLE D+ANGLE C = 180°

50°+ANGLE D+30°=180°

ANGLE D=180-80

ANGLE D=100°

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Answer 2

Hey buddy question isn't clear, so i will find values of all the angles so that u will have ur answer(•‿•)

• In ∆ ABC,

∠A + ∠B + ∠C = 180° ( angle sum property of triangle)

50° + 70° + ∠C = 180°

120° + ∠C = 180°

∠C = 180° - 120°

∠C = 60°

• As line CD is a bisector of ∠C, which divides ∠C into 2 equal parts where ∠ACD = ∠BCD

We can write,

∠ACD + ∠BCD = ∠C

Let ∠ACD = ∠BCD = ∠x

∠x + ∠x = ∠C

2∠x = 60°

∠x = 60/2 = 30°

• In ∆ ADC,

∠A + ∠D + ∠ACD = 180° ( angle sum property of triangle)

50° + ∠D + 30° = 180°

80° + ∠D = 180°

∠D = 180° - 80°

∠D = 100°

• AD is a straight line,

so, ∠ADC + ∠CDB = 180° ( linear pair)

100° + ∠CDB = 180°

∠CDB = 180° - 100°

∠CDB = 80°

HOPE THIS HELPS YOU

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