Question

In 8-to-1 multiplexer, if S2 =1,S1= 0 & S0 = 1, then the output will be​

Answer 1

Explanation:

multiplexer, if S2 =1,S1= 0 & S0 = 1, then the output will be

Answer 2

Given :

8-to-1 multiplexer

S₂ = 1

S₁ = 0

S₀ = 1

To find :

In 8-to-1 multiplexer, if S₂ = 1 , S₁ = 0 & S₀ = 1, then the output will be​

Solution :

n = 8 = 2³

m = log₂n

m = log₂2³ = 3

S₂ S₁ S₀     Y

0   0   0     I₀    

0   0   1      I₁

0   1   0      I₂

0   1   1       I₃

1   0   0      I₄

1   0   1       I₅

1   1   0       I₆

1   1   1        I₇

Y = S₂'S₁'S₀'I₀ + S₂'S₁'S₀I₁ + S₂'S₁S₀'I₂ + S₂'S₁S₀I₃ + S₂S₁'S₀'I₄ + S₂S₁'S₀I₅ + S₂S₁S₀'I₆ + S₂S₁S₀I₇

If S₂ = 1 , S₁ = 0 & S₀ = 1 , then output Y is equal to I₅