Question

in 80 litres of the mixture of milk and water, the respective ratio of the quantities of milk and water is 3:2. 30 litres of the mixture is drawn, find the respective ratio of the quantities of milk in the remaining mixture to the quantity of the water in the drawn mixture?

Answer 1

Total mixture volume = 80 litres
Milk. Water
48 litres. 32 litres

After removing 30 litres of mixture, we have 50 litres left.
now in drawn 30 litres ratio of milk and water must be 3:2,
hence volume of milk drawn =
$\frac{3}{5} \times 30 = 18 \: litres$
Volume of water drawn =
$\frac{2}{5} \times 30 = 12 \: litres$
so Remaining milk = 48 - 18 = 30
drawn water = 12
$\binom{remaining \: milk}{water \: drawn} = \binom{30}{12} = \frac{5}{2}$