In 90 gram of water
a) How many molecules are present in it?
b) What will be the total number of atoms ?
c) Find the volume of same amount of water vapour at STP ( Atomic mass of hydrogen and oxygen are 1 & 16)
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a] To determine the number of molecules in a particular compound, we need to first determine the number of moles present in that mass.
18 g of H2O =1 mole
1 g of H2O=(1÷18) moles
90 g of H2O= (1÷18)×90 moles=5 mol
Now, as we know,
1 mole=6.022×10^(23) molecules
therefore 5 moles= 5×6.022×10^(23)=30.11 ×10^(23) molecules
Hence 90 g of water will contain 30.11×10^(23) molecule..
Explanation:
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